# A rock contains 0.257 mg of Pb-206 for every 1.0 mg of U-238. The half-life for the decay of U-238 to Pb-206 is {eq}4.5 \times 10^9 {/eq} years. How old is the rock?

0.548. 0.552. 207Pb/235U. 206. Pb/. 238. U. 436. 440. 444. Concordia Age = 441.36 ±0.28 Ma. (1σ, decay-const. errs included). MSWD (of concordance) = 3.5 ,.

The series terminates with lead- 206. Other articles where Uranium-238 is discussed: breeder reactor: …a breeder that though uranium-238 (238U) does indeed decay to lead-206 (206Pb), it is not Isotopes Frequently Used in Radiometric Dating. Radioactive Parent Stable Daughter Half Life Values. Product. U-238. Pb-206. 4.5 Billion Years.

A radiometric dating technique uses the decay of $\mathrm{U}-238$ to Pb-206 (the half-life for this process is 4.5 billion years) to determine the age of the oldest rocks on Earth and by implication the age of Earth itself. The oldest uraniumcontaining rocks on Earth contain approximately equal numbers of uranium atoms and lead atoms. SolutionShow Solution. On emission of one alpha particle, the mass number decreases by 4. With the emission of an alpha particle, the atomic number decreases by 2 but when a β-particle is emitted, the atomic number increases by 1. \ [\ce {_92U^238-> [-α]_90X^234}\], where X represents the new nucleus. discordance = (1-(206 Pb/ 238 U age / 207 Pb/ 206 Pb age)*100 - is that right?

Dies nahm man lange an, der Wert sollte bei 235 U : 238 U = 1 : 137,88 liegen. Assuming there was no Pb-206 present when the sample was formed, how old is it? The half-life of U-238 is 4.5 × 109 years.

## You are given a weight ratio of 206Pb to 238U. First thing to do is to convert that to an atomic ratio. For every 1g of 238U there will be 0.376g 206Pb. This is equivalent to:

2017-06-18 In an ore containing Uranium, the ratio of `U^(238)` to `Pb^(206` nuceli is `3`. Calculate the age of the ore, assuming that alll the lead present in the ore is the final stable, product of `U^(238)`. Take the half-like of `U^(238)` to be `4.5 xx 10^(9)` years. In `(4//3) = 0.288`.

### 238 as the there is 137.88 times more U-238 than U-235. This means, the radiogenic Pb-. 206/Pb-207 ratio increases with time. The radiogenic Pb-208/ Pb207

1/2. ≈ 0.7Gyr.

In a sample of rock that does not contain appreciable amounts of Pb-208, the most abundant isotope of lead, we can assume that lead was not present when the rock was formed. In decay from U 238 to Pb 206, each U 238 atom decays and produces 8 \(\alpha\)-particles and hence, total number of \(\alpha\)-particles emitted out = 1.204 x …
The sample contains 40% U-238 and 60% Pb-206. The lead content came from decay of the uranium content.

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Bi-210. 5.013 d. Po-210.

They decay process is `._(92)U^(238) underset((x alpha, y beta))(rarr ._(82)Pb^(206))` `t_(1//2)` of `U^(238) = 4.5 xx 10^(9)` years A sample of rock south America contains equal number of atoms of `U^(238)` and `Pb^(206)`. The age of rock will be
Moreover, in addition to uranium 238, 52 other elements also decay to form lead 206.

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### Uranium (`""_(92)U""^(238)`) decayed to `""_(82)Pb""^(206)`. The process is `""_(92)U""^(238)underset(xalpha,ybeta)to.""_(82)Pb""^(206)` `t""_(1//2)of U""^(238)=4

2019. Size: variable. Technique: lead, pigment.

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### #U^238 rarr Pb^206# (This is not a direct decay but is a process of many alpha decays and beta decay). An alpha particle has 2neutrons and 2protons(A helium nucleus) Thus the combined mass is 4. You only need how many alpha decay it undergoes . This can be determined by an equation like this #206 = 238 - (4x)# Solve for x

2019 . Size: variable Technique: lead, pigment This work illustrates the material change from uranium to lead, known as “uranium-lead dating,” a 14-step transformation process that changes one material into another.